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Chapter 3: Problem 29
Differentiate. $$g(x)=\frac{7^{x}}{4 x+1}$$
Short Answer
Expert verified
The derivative is \( g'(x) = \frac{7^x [ (4x + 1) \, \text{ln} \, 7 - 4 ]}{(4x + 1)^2} \).
Step by step solution
01
Identify Functions
Recognize that the function is a quotient of two functions: the numerator is \( 7^{x} \) and the denominator is \( 4x + 1 \). We'll need to apply the quotient rule for differentiation.
02
Apply the Quotient Rule
The quotient rule states that for \( h(x) = \frac {f(x)}{g(x)} \), the derivative \( h'(x) \) is given by: \[ h'(x) = \frac{f'(x) g(x) - f(x) g'(x)}{[g(x)]^2} \]
03
Differentiate the Numerator
Find the derivative of the numerator \( 7^x \) which is \( 7^x \, \text{ln} \, 7 \).
04
Differentiate the Denominator
Find the derivative of the denominator \( 4x + 1 \), which is simply 4.
05
Substitute into Quotient Rule
Substitute \( f(x) \), \( f'(x) \), \( g(x) \), and \( g'(x) \) into the quotient rule formula: \[ g'(x) = \frac{(7^x \, \text{ln} \, 7)(4x + 1) - (7^x)(4)}{(4x + 1)^2} \]
06
Simplify the Expression
Factor out \( 7^x \) from the numerator to get: \[ g'(x) = \frac{7^x [ (4x + 1) \, \text{ln} \, 7 - 4 ]}{(4x + 1)^2} \]
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
exponential functions
Exponential functions are a special type of function where a constant base is raised to a variable exponent. In the function provided in the exercise, the exponential part is represented by \( 7^x \).
When differentiating an exponential function like \( a^x \) (where \( a \) is a constant), the derivative is \( a^x \, \text{ln} \, a \). This means that for \( 7^x \), the derivative is \( 7^x \, \text{ln} \, 7 \).
This property is used in step 3 of our solution to find the derivative of the numerator.
logarithmic differentiation
Logarithmic differentiation is a technique used to differentiate functions by using the natural logarithm. It's especially helpful when dealing with complicated products, quotients, or exponentials.
In this exercise, although we didn’t explicitly take the logarithm of the entire function, we understand that for exponential functions, knowing the properties of logarithms is crucial.
For example, when differentiating \( 7^x \), we directly use the property of logarithms to get the derivative: \( 7^x \, \text{ln} \, 7 \).
Understanding logarithmic differentiation means recognizing relationships like \( \text{ln}(a^x) = x \, \text{ln}(a) \). Even though we don’t apply this exact relationship here, it forms the basis for why differentiating exponentials involves a natural logarithm.
derivative
The derivative measures how a function changes as its input changes. In simpler terms, it gives us the rate of change or the slope of a function at any given point.
In our exercise, we're asked to find the derivative of a quotient: \( g(x) = \frac{7^{x}}{4 x + 1} \). To do this, we use the quotient rule, which is handy for differentiating functions that are ratios of two other functions.
The quotient rule states:
- \[ h'(x) = \frac{f'(x) g(x) - f(x) g'(x)}{[g(x)]^2} \]
Here, we find the derivatives of the numerator \( 7^x \) and the denominator \( 4x + 1 \), and then plug these into the quotient rule formula.
This process helps us find how the function \( g(x) \) changes concerning \( x \), giving us the final simplified expression.
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